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0=4w^2-88w-11
We move all terms to the left:
0-(4w^2-88w-11)=0
We add all the numbers together, and all the variables
-(4w^2-88w-11)=0
We get rid of parentheses
-4w^2+88w+11=0
a = -4; b = 88; c = +11;
Δ = b2-4ac
Δ = 882-4·(-4)·11
Δ = 7920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7920}=\sqrt{144*55}=\sqrt{144}*\sqrt{55}=12\sqrt{55}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-12\sqrt{55}}{2*-4}=\frac{-88-12\sqrt{55}}{-8} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+12\sqrt{55}}{2*-4}=\frac{-88+12\sqrt{55}}{-8} $
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